Optimal. Leaf size=133 \[ \frac{a^3}{8 d (a-a \sin (c+d x))^2}-\frac{5 a^2}{4 d (a-a \sin (c+d x))}-\frac{a^2}{8 d (a \sin (c+d x)+a)}-\frac{a \sin ^2(c+d x)}{2 d}-\frac{a \sin (c+d x)}{d}-\frac{39 a \log (1-\sin (c+d x))}{16 d}-\frac{9 a \log (\sin (c+d x)+1)}{16 d} \]
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Rubi [A] time = 0.111147, antiderivative size = 133, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.12, Rules used = {2836, 12, 88} \[ \frac{a^3}{8 d (a-a \sin (c+d x))^2}-\frac{5 a^2}{4 d (a-a \sin (c+d x))}-\frac{a^2}{8 d (a \sin (c+d x)+a)}-\frac{a \sin ^2(c+d x)}{2 d}-\frac{a \sin (c+d x)}{d}-\frac{39 a \log (1-\sin (c+d x))}{16 d}-\frac{9 a \log (\sin (c+d x)+1)}{16 d} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \sin (c+d x) (a+a \sin (c+d x)) \tan ^5(c+d x) \, dx &=\frac{a^5 \operatorname{Subst}\left (\int \frac{x^6}{a^6 (a-x)^3 (a+x)^2} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{x^6}{(a-x)^3 (a+x)^2} \, dx,x,a \sin (c+d x)\right )}{a d}\\ &=\frac{\operatorname{Subst}\left (\int \left (-a+\frac{a^4}{4 (a-x)^3}-\frac{5 a^3}{4 (a-x)^2}+\frac{39 a^2}{16 (a-x)}-x+\frac{a^3}{8 (a+x)^2}-\frac{9 a^2}{16 (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{a d}\\ &=-\frac{39 a \log (1-\sin (c+d x))}{16 d}-\frac{9 a \log (1+\sin (c+d x))}{16 d}-\frac{a \sin (c+d x)}{d}-\frac{a \sin ^2(c+d x)}{2 d}+\frac{a^3}{8 d (a-a \sin (c+d x))^2}-\frac{5 a^2}{4 d (a-a \sin (c+d x))}-\frac{a^2}{8 d (a+a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 0.439807, size = 133, normalized size = 1. \[ -\frac{a \sin (c+d x) \tan ^4(c+d x)}{d}-\frac{a \left (2 \sin ^2(c+d x)-\sec ^4(c+d x)+6 \sec ^2(c+d x)+12 \log (\cos (c+d x))\right )}{4 d}-\frac{5 a \left (6 \tan (c+d x) \sec ^3(c+d x)-8 \tan ^3(c+d x) \sec (c+d x)-3 \left (\tanh ^{-1}(\sin (c+d x))+\tan (c+d x) \sec (c+d x)\right )\right )}{8 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.072, size = 205, normalized size = 1.5 \begin{align*}{\frac{a \left ( \sin \left ( dx+c \right ) \right ) ^{8}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{a \left ( \sin \left ( dx+c \right ) \right ) ^{8}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{a \left ( \sin \left ( dx+c \right ) \right ) ^{6}}{2\,d}}-{\frac{3\,a \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{4\,d}}-{\frac{3\, \left ( \sin \left ( dx+c \right ) \right ) ^{2}a}{2\,d}}-3\,{\frac{a\ln \left ( \cos \left ( dx+c \right ) \right ) }{d}}+{\frac{a \left ( \sin \left ( dx+c \right ) \right ) ^{7}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{3\,a \left ( \sin \left ( dx+c \right ) \right ) ^{7}}{8\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{3\,a \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{8\,d}}-{\frac{5\,a \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{8\,d}}-{\frac{15\,a\sin \left ( dx+c \right ) }{8\,d}}+{\frac{15\,a\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.11454, size = 143, normalized size = 1.08 \begin{align*} -\frac{8 \, a \sin \left (d x + c\right )^{2} + 9 \, a \log \left (\sin \left (d x + c\right ) + 1\right ) + 39 \, a \log \left (\sin \left (d x + c\right ) - 1\right ) + 16 \, a \sin \left (d x + c\right ) - \frac{2 \,{\left (9 \, a \sin \left (d x + c\right )^{2} + 3 \, a \sin \left (d x + c\right ) - 10 \, a\right )}}{\sin \left (d x + c\right )^{3} - \sin \left (d x + c\right )^{2} - \sin \left (d x + c\right ) + 1}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.54359, size = 440, normalized size = 3.31 \begin{align*} \frac{8 \, a \cos \left (d x + c\right )^{4} + 6 \, a \cos \left (d x + c\right )^{2} - 9 \,{\left (a \cos \left (d x + c\right )^{2} \sin \left (d x + c\right ) - a \cos \left (d x + c\right )^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 39 \,{\left (a \cos \left (d x + c\right )^{2} \sin \left (d x + c\right ) - a \cos \left (d x + c\right )^{2}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (4 \, a \cos \left (d x + c\right )^{4} + 6 \, a \cos \left (d x + c\right )^{2} - 3 \, a\right )} \sin \left (d x + c\right ) + 2 \, a}{16 \,{\left (d \cos \left (d x + c\right )^{2} \sin \left (d x + c\right ) - d \cos \left (d x + c\right )^{2}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39309, size = 153, normalized size = 1.15 \begin{align*} -\frac{16 \, a \sin \left (d x + c\right )^{2} + 18 \, a \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) + 78 \, a \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) + 32 \, a \sin \left (d x + c\right ) - \frac{2 \,{\left (9 \, a \sin \left (d x + c\right ) + 7 \, a\right )}}{\sin \left (d x + c\right ) + 1} - \frac{117 \, a \sin \left (d x + c\right )^{2} - 194 \, a \sin \left (d x + c\right ) + 81 \, a}{{\left (\sin \left (d x + c\right ) - 1\right )}^{2}}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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